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5n^2+4=745n
We move all terms to the left:
5n^2+4-(745n)=0
a = 5; b = -745; c = +4;
Δ = b2-4ac
Δ = -7452-4·5·4
Δ = 554945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-745)-\sqrt{554945}}{2*5}=\frac{745-\sqrt{554945}}{10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-745)+\sqrt{554945}}{2*5}=\frac{745+\sqrt{554945}}{10} $
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